Answer:
[tex](a)=HClO_{3}[/tex], [tex](b)=HCl[/tex], [tex](c)=NaOH[/tex]
Explanation:
[tex](a)=HClO_{3}[/tex]
[tex]HClO_{3}[/tex] is more acidic then [tex]HClO[/tex] due to the [tex]ClO^{-}[/tex] is strongest base from the[tex]ClO_{3}^{-}[/tex] so [tex]HClO_{3}[/tex] is more acidic then the [tex]HClO[/tex].
[tex](b)=HCl[/tex]
[tex]HCl[/tex] is more acidic from the [tex]CH_{3}COOH[/tex] because [tex]CH_{3}COOH[/tex] is weak acid and [tex]HCl[/tex] is strongest acid .
[tex](c)=NaOH[/tex]
[tex]NaOH[/tex] is strongest base from the [tex]CH_{3}NH_{2}[/tex] because [tex]NaOH[/tex] break down in form of [tex]H^{+}[/tex] and [tex]OH^{-}[/tex].[tex]OH^{-}[/tex] is strongest basic in nature.[tex]CH_{3}NH_{2}[/tex] break down in two parts [tex]H^{+}[/tex] and [tex]CH_{3}NH^{-}[/tex].[tex]OH^{-}[/tex]is more basic from the [tex]CH_{3}NH^{-}[/tex] so [tex]NaOH[/tex] is more basic from the [tex]CH_{3}NH_{2}[/tex].