Answer:
The fraction is [tex]\frac{6}{13} .[/tex]
Step-by-step explanation:
There is a data missing in the question so the complete question is below:
If 1 is added to both numerator and denominator of a fraction,the fraction become 1/2 if 8 is added to both, the fraction become 2/3 what is the fraction?
Now, to find the fraction.
Let the fraction be [tex]\frac{x}{y} .[/tex]
If 1 is added to both numerator and denominator of a fraction,the fraction become 1/2.
[tex]\frac{x+1}{y+1}=\frac{1}{2}[/tex]
By cross multiplying we get:
[tex]2x+2=y+1[/tex]
Subtracting both sides by [tex]1[/tex] we get:
[tex]2x+1=y[/tex]
[tex]y=2x+1[/tex] ......(1)
Now, if 8 is added to both, the fraction become 2/3:
[tex]\frac{x+8}{y+8} =\frac{2}{3}[/tex]
By cross multiplying we get:
[tex]3x+24=2y+16[/tex]
Subtracting both sides by 16 we get:
[tex]3x+8=2y[/tex]
Substituting the value of [tex]y[/tex] from equation (1) we get:
[tex]3x+8=2(2x+1)[/tex]
[tex]3x+8=4x+2[/tex]
Adding both sides by 2 we get:
[tex]3x+6=4x[/tex]
Subtracting both sides by 3[tex]x[/tex] we get:
[tex]6=x[/tex]
[tex]x=6.[/tex]
Now, substituting the value of [tex]x[/tex] in equation (1):
[tex]y=2x+1\\y=2\times 6+1\\y=12+1\\y=13.[/tex]
Therefore, the fraction is [tex]\frac{6}{13} .[/tex]