Question

Leah flips a coin, and then she spins a spinner with 3 equal sections colored red, green, and blue. What is the probability that
• the coin flips heads, and
• the spinner lands on either red or blue?
Enter your answer as a percentage, to the nearest percent.​

Answer 1

Answer: the first one is a one In two probability and the spinner is two of three probability

Step-by-step explanation:

Answer 2

Probability of an event is the measurement of its chance of occurrence. The needed probability is evaluated to be 33.33% approx.

How to calculate the probability of an event?

Suppose that there are finite elementary events in the sample space of the considered experiment, and all are equally likely.

Then, suppose we want to find the probability of an event E.

Then, its probability is given as

$P(E) = \dfrac{\text{Number of favorable cases}}{\text{Number of total cases}} = \dfrac{n(E)}{n(S)}$

where favorable cases are those elementary events who belong to E, and total cases are the size of the sample space.

What is chain rule in probability?

For two events A and B, by chain rule, we have:

P(A \cap B) = P(B)P(A|B) = P(A)P(B|A)

where P(A|B) is probability of occurrence of A given that B already occurred.

If A and B are independent events, then we get:

$P(A|B) = P(A) \\P(B|A) = P(B)\\P(A \cap B) = P(A)P(B)$

How to convert percent to probability?

Percent counts the number compared to 100 whereas probability counts it compare to 1.

So, if we have a%, that means for each 100, there are 'a' parts. If we divide each of them with 100, we get:

For each 1, there are a/100 parts.

Thus, 50% = 50/100 = 0.50 (in probability)

For this case, we know that the result of coin flip and result on spin on spinner are independent (at least ideally, assumingly).

Let  A = Coin flips heads

B = The spinner lands on either red or blue

Now, P(A) = 1/2 (as ways to get head in a coin is 1 and there are total 2 results)

Now, spinner has total of 3 sections, and 'red or blue' covers 2 of them, thus, we get:

P(B) = 2/3

Thus, the probability that the coin flips heads, and the spinner lands on either red or blue, which is $P(A \cap B)$ is evaluated as:

$P(A \cap B) = P(A)P(B) = \dfrac{1}{2}.\dfrac{2}{3} = \dfrac{1}{3} \approx 0.3333 = 33.33\%$

Thus, the needed probability is evaluated to be 33.33% approx.

Learn more about probability here:

brainly.com/question/1210781