Question

An information technology company produces 48% of its computer chips at a plant in st. louis and the remainder of its chips at a plant in chicago. it is known that 0.9% of the chips produced in st. louis are defective, while 0.9% of the chips produced at the plan in chicago are defective. what is the probability that a randomly chosen computer chip produced by this company is defective and was produced in st. louis?

Answer 1

Answer:

0.432%

Explanation:

We can assume a total production of 100,000 chips between both plants, that means that 48,000 chips are produced in St. Louis and 52,000 in Chicago.

Since 0.9% of the chips produced in St. Louis and Chicago are defective, that equals 900 defective chips in total: 432 from St. Louis and 468 from Chicago.

Since the total number of defective chips from St. Louis is 432, the probability that a randomly chosen chip is both defective and produced in St. Louis = total number of defective chips produced in St. Louis / total number of chips produced in both plants = 432 chips / 100,000 chips = 0.00432 or 0.432%