Respuesta :
Answer:
Genotype frequency for heterozygotes is equal to [tex]37.7[/tex] %
Explanation:
Given
Number of individuals with genotype HH - [tex]422[/tex]
Number of individuals with genotype hh - [tex]201[/tex]
Number of individuals with genotype Hh - [tex]377[/tex]
Sum of all individuals with varied genotypes
[tex]422 + 377 + 201\\= 1000[/tex]
Genotype frequency of any specific genotype with in a population is equal to total number of individuals with that genotype divided by total population.
Hh is a heterozygous genotype.
Thus, genotype frequency for heterozygotes
[tex]\frac{377}{1000} * 100\\= 37.7[/tex]
Genotype frequency for heterozygotes is equal to [tex]37.7[/tex] %
To get the frequency of heter0zyg0tes, we just need to divide the total number of heter0zyg0us individuals by the population size. In this example, the genotype frequency for heterozygotes is 0.377 = 37.7%.
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Available data:
- allele H is dominant over h
- 422 HH individuals
- 377 Hh individuals
- 201 hh individuals
- Total number of individuals = N = 422 + 377 + 201 = 1000
We need to get the genotypic frequency of heter0zyg0us individuals in this Tibet population.
We already know the number of heter0zyg0us individuals and the total number of individuals in the population. These data are enough to calculate genotypic frequency -F(Hh)-.
All we need to do is to divide the number of heter0zyg0us individuals by the population size.
- Hh = 377 individuals
- N = 1000 individuals
F(Hh) = Hh/N = 377 / 1000 = 0.377 = 37.7%
So, the genotype frequency for heter0zyg0tes is 0.377 or 37.7%.
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