Respuesta :
Answer:
135 degrees
[tex]S45^{0}E[/tex]
Step-by-step explanation
Consider the attached diagram
we are required to find the bearing of the aeroplane,
Consider the right angled triangle BOE
|OB|=4 unit
|AB|=4 Units
[tex]Tan \alpha =\frac{Opposite}{Adjacent} =\frac{4}{4} \\\\\alpha=Tan^{-1} 1=45 degrees[/tex]
The Bearing of the Aeroplane is therefore given:
(i)From North Clockwise as: 90+45 =135 degrees
(ii)From a North South Line as [tex]S45^{0}E[/tex]

When a student is given a mathematical problem that involves the use of angles, then one of the ways he can solve this is the use of bearing.
What is Bearing?
This refers to the angle of degrees which is measured from the North in clockwise motion.
To find the bearing of the aeroplane,
we would have to look at the right angle labelled BOE
|OB|= 4 units
|AB| = 4 units
[tex]\alpha[/tex]= Tan⁻¹1= 45 degrees
With this in mind, the bearing of the airplane from the:
- North Clockwise direction is 90+45= 135 degrees
- North South line is 45 degrees South East
Read more about bearing here:
https://brainly.com/question/23427938
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