Question

Calculate the number of C atoms in 0.190 mole C6H14O.
can anyone help me on this one?

Answer 1

In 0.190 mole of C6H14O, there is 0.190*6 (number of C in one molecule) = 1.140 mole of C atoms. The total number of C atoms = 1.14 * 6*$10^{23}$ (atoms of C in one mole) = 6.84*$10^{23}$ atoms.