Question

What is the mass of an object that needs a force of 6 600N to increase its speed from rest 107 m/s in 2.3 seconds?

Answer 1

We know that:
a=(v-u)/t
a=(107m/s-0)/2,3s
a=46,5m/s²
Now:
F=ma
6600N=m*46,5m/s²
m=6600N/46,5m/s²
m≈142kg

Answer 2

The mass of the object that requires the given force to increase its speed is 141.87 kg.

The given parameters;

• mass of the object, = m
• force applied on the object, F = 6,600 N
• speed of the object, v = 107 m/s
• time of motion of the object, t = 2.3 s

The mass of the object is determined by applying Newton's second law of motion as shown below;

F = ma

where;

• a is the acceleration of the object
• m is the mass of the object

$F = ma = \frac{mv}{t} \\\\mv = Ft\\\\m = \frac{Ft}{v} \\\\m = \frac{6,600 \times 2.3}{107} \\\\m = 141.87 \ kg$

Thus, the mass of the object that requires the given force to increase its speed is 141.87 kg.

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