Answer:
The channel height is 0.0510 cm.
Explanation:
Given that,
Width w= 2 cm
Dynamic viscosity [tex]\mu= 0.0087\ g/cm-s[/tex]
Discharge flow rate Q= 2 ml/s
Shear stress [tex]\tau= 20\ dynes/cm²[/tex]
We need to calculate the channel heights
Using formula of maximum shear stress
[tex]\tau=\dfrca{6Q\mu}{H^2w}[/tex]
[tex]H=\sqrt{\dfrac{6Q\mu}{\tau w}}[/tex]
Put the value into the formula
[tex]H=\sqrt{\dfrac{6\times2\times0.0087}{20\times2}}[/tex]
[tex]H=0.0510\ cm[/tex]
Hence, The channel height is 0.0510 cm.