Solution:
Let "a" be the number of 56 cent stamps
Let "b" be the number of 41 cent stamps
The number of 56-cent stamps she bought was 10 less than 4 times the number of 41-cent stamps
number of 56-cent stamps = 4 times the number of 41-cent stamps - 10
a = 4b - 10 -------- eqn 1
Yumi spent $34.15 buying stamps
Therefore,
[tex]56 \times a + 41 \times b = 3415[/tex]
56a + 41b = 3415 ------- eqn 2
Substitute eqn 1 in eqn 2
56(4b - 10) + 41b = 3415
224b - 560 + 41b = 3415
265b = 3975
Substitute b = 15 in eqn 1
a = 4(15) - 10
a = 60 - 10
Thus number of 56 cent stamps is 50 and number of 41 cent stamps is 15