Answer:
Step-by-step explanation:
Given that a simple random sample of 40 ten-gram portions of the food item is obtained and results in a sample mean of x overbarequals2.5 insect fragments per ten-gram portion.
a) By central limit theorem for samples randomly drawn with large sample sizes (atleast 30) the sample mean follows a normal distribution irrespective of the original distribution it belonged to.
b) Mean of X bar = Sample mean = 5
Std error of x bar = s/sqrt n = [tex]\frac{289}{\sqrt{40} } \\=45.695[/tex]
c) P( x bar >5.8) = P(Z>[tex]\frac{5.8-5}{45.695} \\=0.0176[/tex])
=0.4930