Answers:
1) flow of traffic = [tex]1198.8 veh/h[/tex]
2) average speed = [tex]34.09 mi/h[/tex]
3)density of traffic = [tex]34.34 veh/mi[/tex]
Explanation:
1) to find flow of traffic
we use the relation
[tex]q=1/h[/tex]
where q is the traffic flow and h is average time headway.
[tex]h= 3s[/tex] [tex](given)[/tex]
insert the value
[tex]q=1/3=0.333veh/s=1198.8veh/h[/tex]
2) to find average traffic speed
use the relation
[tex]u=S/h[/tex]
where u is average speed S is average spacing and h average time
[tex]S= 150 ft[/tex] [tex](given)[/tex]
so inserting the values
[tex]u= 150/3*3600/5280=34.09 mi/h[/tex]
3) density of traffic
[tex]K=q/u[/tex]
where K is density of traffic q is flow of traffic and u is average speed
inserting values from above solved parts
[tex]K=1198.8/34.09=34.34 veh/mi[/tex]