Answer:
(a) The probability that all members of the committee are men is 0.3818.
(b) The probability that at least 1 member of the committee is a woman is 0.6182.
Step-by-step explanation:
The number of men in the board of directors is 9.
The number of women in the board of directors is 3.
A committee of three is randomly selected from the board.
(a)
Compute the probability that all members of the committee are men as follows:
P (Selecting 3 men) = n (Selecting 3 men) ÷ n (Selecting 3 members)
[tex]=\frac{{9\choose 3}}{{12\choose 3}}\\= \frac{84}{220} \\=0.3818[/tex]
Thus, the probability that all members of the committee are men is 0.3818.
(b)
Compute the probability that at least 1 member of the committee is a woman as follows:
P (At least 1 woman) = 1 - P (All 3 men)
[tex]=1-0.3818\\=0.6182[/tex]
Thus, the probability that at least 1 member of the committee is a woman is 0.6182.