Answer:
Explanation:
In this example, total number of radiographs are 156. Hence, n=156 (A+B+C+D).
True positive results= 40
False Positive result= 4
False negative result= 3
Hence the contingency table can be made as follows:
Lesion present Lesion Absent Total
Test positive 40 (A) 4 (B) A+B= 44
Test negative 3 (C) 109 (D) C+D= 112
A+C= 43 B+D= 113 n= 156
1) Sensitivity= A / A+C= 40/43 =93.02%
2) Specificity= D/ B +D= 109/113 = 96.46%
3) Accuracy= A+D/ A+B+C+D = 95.51%