Question

Sequoia measures the wavelength of the sound in a Kundt’s tube to be 0.340 m. If the instructor tells her that the frequency driving the sound in the tube is 997 Hz, she will calculate a speed of sound in air of____________.a. 2930 m/sb. 343 m/sc. She cannot calculate this with the available datad. 339 m/s

Answer 1

Answer:

Option (d) 339 m/s is the correct answer in this case.

Explanation:

1) The problem gives us the wavelength λ = 0.340 meter, and the frequency f = 997 Hz.

2) The speed of sound in terms of frequency " f " and wavelength " λ " is

V = f × λ

3) Putting these values into the equation, V = 997 × 0.340.

4) V = 338.98 m/s ≅ 339 m/s .

Answer 2

Answer:

339 m/s.

Explanation:

For a wave,

V = f × λ

where,

wavelength, λ = 0.340 m

frequency, f = 997 Hz

velocity, v

Inputting these values into the equation, we have:

v = 997 × 0.340.

= 338.98 m/s

≅ 339 m/s .