Answer:
The water content of this borrow material is 0.194
Explanation:
Given that,
Weight of material = 123 pcf
Weight of dry sample = 103 pcf
We need to calculate the water content of this borrow material
Using formula of water content
[tex]\gamma_{d}=\dfrac{\gamma}{1+W_{w}}[/tex]
[tex]W_{w}=\dfrac{\gamma-\gamma_{d}}{\gamma_{d}}[/tex]
Where, w = weight of water
[tex]\gamma_{d}[/tex] = dry unit weight
[tex]\gamma[/tex] = unit weight
Put the value into the formula
[tex]W_{w}=\dfrac{123-103}{103}[/tex]
[tex]W_{w}=0.194[/tex]
Hence, The water content of this borrow material is 0.194