Your question is difficult to understand, that is why I am going to edit your question as follow:
Edited Question:
Cone A and B both have a volume of 48π Cubic units but have different dimensions. Cone A has a radius=6 units and a height=4 units.
Find the one possible radius and height for cone B be to have the same volume as cone A.
Answer:
Radius of cone B= 6units
Height of cone B=units
Step-by-step explanation:
As we know the formula for the volume of a cone is
[tex]V=\pi\ r^{2}\frac{h}{3}[/tex]
If volume of A and Volume B is given as same, thus
[tex]V_{A}=V_{B}[/tex]
[tex]\pi\ (R_{A}) ^{2}\frac{H_{A} }{3} =\pi\ (R_{B}) ^{2}\frac{H_{B} }{3}[/tex]
comparing equations above, we get
[tex]R_{A}=R_{B}\\H_{A}=H_{B}[/tex]
Thus, Radius of cone A=6units
and
Height of cone B= 4units