Respuesta :
Answer:
a. 01111111 11110000 01100111 01111101 dotted decimal notation:
(127.240.103.125)
b. 10101111 11000000 11111000 00011101 dotted decimal notation: (175.192.248.29)
c. 11011111 10110000 00011111 01011101 dotted decimal notation:
(223.176.31.93)
d. 11101111 11110111 11000111 00011101 dotted decimal notation:
(239.247.199.29)
a. 208.34.54.12 class is C
b. 238.34.2.1 class is D
c. 242.34.2.8 class is E
d. 129.14.6.8 class is B
a.11110111 11110011 10000111 11011101 class is E
b.10101111 11000000 11110000 00011101 class is B
c.11011111 10110000 00011111 01011101 class is C
d.11101111 11110111 11000111 00011101 class is D
Explanation:
8 a. 01111111 11110000 01100111 01111101
we have to convert this binary notation to dotted decimal notation.
01111111 = 0*2^7 + 1*2^6 + 1*2^5 + 1*2^4 + 1*2^3 + 1*2^2 + 1*2^1 + 1*2^0
= 0 + 1*64 + 1*32 + 1*16 + 1*8 + 1*4 + 1*2 + 1
= 64 + 32 + 16 + 8 + 4 + 2 + 1
= 127
11110000 = 1*2^7 + 1*2^6 + 1*2^5 + 1*2^4 + 0*2^3 + 0*2^2 + 0*2^1 + 0*2^0
= 1*128 + 1*64 + 1*32 + 16 + 0 + 0 + 0 + 0
= 128 + 64 + 32 + 16
= 240
01100111 = 0*2^7 + 1*2^6 + 1*2^5 + 0*2^4 +0*2^3 + 1*2^2 + 1*2^1 + 1*2^0
= 0 + 1*64 + 1*32 + 0 + 0 + 4 + 2 + 1
= 64 + 32 + 4 + 2 + 1
= 103
01111101 = 0*2^7 + 1*2^6 + 1*2^5+ 1*2^4 +1*2^3 +1*2^2 + 0*2^1 + 1*2^0
= 0 + 1*64 + 1*32 + 1*16 + 1*8 + 1* 4 + 0 + 1
= 64 + 32 + 16 + 8 + 4 + 1
= 125
So the IP address from binary notation 01111111 11110000 01100111 01111101 to dotted decimal notation is : 127.240.103.125
b) 10101111 11000000 11111000 00011101
10101111 = 1*2^7 + 0*2^6 + 1*2^5 + 0*2^4 + 1*2^3 + 1*2^2 + 1*2^1 + 1*2^0
= 175
11000000 = 1*2^7 + 1*2^6 + 0*2^5 + 0*2^4 + 0*2^3 + 0*2^2 + 0*2^1 + 0*2^0
= 192
11111000 = 1*2^7 + 1*2^6 + 1*2^5 + 1*2^4 +1*2^3 + 0*2^2 + 0*2^1 + 0*2^0
= 248
00011101 = 0*2^7 + 0*2^6 + 0*2^5 + 1*2^4 +1*2^3 + 1*2^2 + 0*2^1 + 1*2^0
= 29
So the IP address from binary notation 10101111 11000000 11111000 00011101 to dotted decimal notation is : 175.192.248.29
c) 11011111 10110000 00011111 01011101
11011111 = 1*2^7 + 1*2^6 + 0*2^5 + 1*2^4 +1*2^3 + 1*2^2 + 1*2^1 + 1*2^0
= 223
10110000 = 1*2^7 + 0*2^6 + 1*2^5 + 1*2^4 +0*2^3 + 0*2^2 + 0*2^1 + 0*2^0
= 176
00011111 = 0*2^7 + 0*2^6 + 0*2^5 + 1*2^4 +1*2^3 + 1*2^2 + 1*2^1 + 1*2^0
= 31
01011101 = 0*2^7 + 1*2^6 + 0*2^5 + 1*2^4 +1*2^3 + 1*2^2 + 0*2^1 + 1*2^0
= 93
So the IP address from binary notation 11011111 10110000 00011111 01011101 to dotted decimal notation is :223.176.31.93
d) 11101111 11110111 11000111 00011101
11101111 = 1*2^7 + 1*2^6 + 1*2^5 + 0*2^4 +1*2^3 + 1*2^2 + 1*2^1 + 1*2^0
= 239
11110111 = 1*2^7 + 1*2^6 + 1*2^5 + 1*2^4 +0*2^3 + 1*2^2 + 1*2^1 + 1*2^0
= 247
11000111 = 1*2^7 + 1*2^6 + 0*2^5 + 0*2^4 +0*2^3 + 1*2^2 + 1*2^1 + 1*2^0
= 199
00011101 = 0*2^7 + 0*2^6 + 0*2^5 + 1*2^4 +1*2^3 + 1*2^2 + 0*2^1 + 1*2^0
= 29
So the IP address from binary notation 11101111 11110111 11000111 00011101 to dotted decimal notation is : 239.247.199.29
9. In order to the find the class check the first byte of the IP address which is first 8 bits and check the corresponding class as follows:
Class A is from 0 to 127
Class B is from 128 to 191
Class C is from 192 to 223
Class D is from 224 to 239
Class E is from 240 to 255
a. 208.34.54.12
If we see the first byte of the IP address which is 208, it belongs to class C as class C ranges from 192 to 223.
b. 238.34.2.1
If we see the first byte of the IP address which is 238, it belongs to class D as Class D ranges from 224 to 239.
c. 242.34.2.8
If we see the first byte of the IP address which is 242, it belongs to class E as Class E ranges from 240 to 255.
d. 129.14.6.8
If we see the first byte of the IP address which is 129, it belongs to class B as Class B ranges from 128 to 191.
10. In order to find the class of the IP addresses in easy way, start checking bit my bit from the left of the IP address and follow this pattern:
0 = Class A
1 - 0 = Class B
1 - 1 - 0 = Class C
1 - 1 - 1 - 0 = Class D
1 - 1 - 1 - 1 = Class E
a. 11110111 11110011 10000111 11011101
If we see the first four bits of the IP address they are 1111 which matches the pattern of class E given above. So this IP address belongs to class E.
b. 10101111 11000000 11110000 00011101
If we see the first bit is 1, the second bit is 0 which shows that this is class B address as 1 0 = Class B given above.
c. 11011111 10110000 00011111 01011101
The first bit is 1, second bit is 1 and third bit is 0 which shows this address belongs to class C as 110 = Class C given above.
d. 11101111 11110111 11000111 00011101
The first bit is 1, the second bit is also 1 and third bit is also 1 which shows that this address belongs to class D.
