Question

A) Describe the path one a pair of electrons, during the light reactions, starting with the electron donor molecule (water) until they are given to NADPH.
B) What is the purpose of the electron transport from Photosystem II to Photosystem I?
C) What is the final purpose of those electrons, where does NADPH take them to?

Answer 1

Photosystem I and photosystem II are the two places that require light during photophosphorylation.Photosystem I contains the P700 pigment complex, which needs light for the excitation

Answer 2

A) The path one a pair of electrons, during the light reactions is - water > P700 pigment complex > NADP+ > NADH+ > NADPH.

B) The purpose of the electron transport from Photosystem II to Photosystem I - to carryout reaction to the electron transport system

C) The purpose of these electrons is to generate ATP by the activation of ATP synthase through the electron transport chain.

A) Photosystem I and photosystem II are the two distinct centers that require light during photophosphorylation.

• Photosystem I contains the P700 pigment complex, which needs light for the excitation of electrons
• These electrons reduce the primary acceptor carrier molecule and are passed to NADP+
• combining NADH+ with electrons to form the high-energy compound NADPH.  

B). The electrons produced by the splitting of water molecules into oxygen are transported to photosystem I to carry out the reactions in the electron transport chain (ETC).  

C). The purpose of these electrons is to generate ATP by the activation of ATP synthase through the electron transport chain.

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