Question

It takes 3.0 μJ of work to move a 17 nC charge from point A to B. It takes -6.5 μJ of work to move the charge from C to B. Part A What is the potential difference VC−VA? Express your answer using two significant figures.

Answer 1

Answer:

Explanation:

Charge move from A to B

Work to move from A to B = 3 μJ

Work to move from C to B = - 6.5 μJ

charge, q = 17 nC = 17 x 10^-9 C

VB - VA = q x work from A to B

VB - VA = 17 x 10^-9 x 3 x 10^-6

VB - VA = 51 x 10^-15 J     .... (1)

VC - VB = q x work from C to B

VC - VB = - 17 x 10^-9 x 6.5 x 10^-6

VC - VB = - 110.5 x 10^-15 J    ... (2)

Add equation (1) and (22), we get

VC - VA = VC - VB + VB - VA

VC - VA = -110.5 x 10^-15 + 51 x 10^-15

VC - VA = - 59.5 x 10^-15 V

Answer 2

Answer:

The potential difference VC−VA is 533.33 V

Explanation:

please look at the solution in the attached Word file