Answer:
The uncertainty in this calculation is 90 cm³
(d) is correct option.
Explanation:
Given that,
Radius of cylindrical bottle = 4.5 cm
Height = 30.0 cm
Uncertainty in both = 0.1 cm
Volume of bottle = 1908.5 cm³
We need to calculate the uncertainty in this calculation
Using formula of volume
[tex]V=\pi r^2 h[/tex]
[tex]\dfrac{\Delta V}{V}=\dfrac{2\Delta r}{r}+\dfrac{\Delta h}{h}[/tex]
Put the value into the formula
[tex]\dfrac{\Delta V}{1908.5}=\dfrac{0.2}{4.5}+\dfrac{0.1}{30}[/tex]
[tex]\Delta V=1908.5\times(\dfrac{0.2}{4.5}+\dfrac{0.1}{30})[/tex]
[tex]\Delta V=90\ cm^3[/tex]
Hence, The uncertainty in this calculation is 90 cm³