Answer:
The number of adults attending the zoo is 12, and the number of children attending is 17.
Step-by-step explanation:
Let [tex]a[/tex] be the number of adults, and [tex]c[/tex] be the number of children attending the zoo, then system representing the situation is
(1). [tex]10a+6c=222[/tex] (this says that the total cost of the tickets is $222)
(2). [tex]a+c=29[/tex] (this says that a total of 29 people attended the zoo)
We solve this system by solving for [tex]a[/tex] in equation (2), and substituting that into equation (1) as follows:
[tex]a =29-c[/tex]
[tex]10(29-c)+6c = 222[/tex]
expand and get
[tex]290-10c+6c=222[/tex]
[tex]290-4c=222[/tex]
solving for [tex]c[/tex] we get:
[tex]\boxed{ c=17}[/tex]
Now we put this value of [tex]c[/tex] into equation (2), and solve for [tex]a[/tex] :
[tex]a+ 17 =29[/tex]
[tex]\boxed{ a= 12}[/tex]
Thus, the number of adults attending the zoo is 12, and the number of children attending is 17.