Step-by-step explanation:
Remember, the binomial distribution model formula is:[tex]P (X "sucesses")=\frac{n!}{x!(n-x)!}P^{x }(1-p)^(n-x)}[/tex]
Using the medical sector scenario of a binomial random variable for example if 90% of adults with allergies report symptomatic relief with a specific medication. And we give the medication to 10 new patients with allergies, what is the probability that it is effective in exactly seven?
Solution
The 'success' = the outcome
The probability of success for each person = 0.9 (90/100)
The final assumption is that the replications are independent, and it is reasonable to assume that this is true.
Number of observations (adults observed) is n=10
Number of successes or events of interest is x=7
p=0.90
The probability of 7 successes is:
[tex]P (X "sucesses")=\frac{10!}{7!(10-7)!}0.90^{7}(1-0.90)^(10-7)}[/tex]
120 × 0.0004782969 = 0.057395628 or 5.7%
Which clearly implies there is a 5.7% probability that exactly 7 of 10 patients will report relief from symptoms when the probability that any one reports relief is 90%.