Question

A rectangle has an area of 192 square inches. Find it’s length and width if the length is 3 times the width

Answer 1

Answer: Width = 9 inches

Length = 12 inches

Step-by-step explanation: A = (w+3)(w)

A = w2 + 3w = 108

w2 + 3y - 108 = 0

This is the factor of the problem: (w - 9) (w + 12) = 0

This equals to w + 12 = 0

w = -12

Then the final answer would be Width = 9 inches

Length = 12 inches.

Hope this helps!

I am joyous to assist anytime!

~Jarvis

Answer 2

The length and width of the rectangle are 24 and 8 inches respectively.

• Let the length of the rectangle be L.

• Let the width of the rectangle be W.

Given the following data:

Area of rectangle = 192 square inches.

To determine the length and width of the rectangle:

Translating the word problem into an algebraic equation, we have;

$L=3W$   ...equation 1.

Mathematically, the area of a rectangle is given by the formula;

$A=LW$   .....equation 2.

Substituting the values into the formula, we have;

$192 =3W(W)\\\\192=3W^2\\\\W^2=\frac{192}{3} \\\\W^2=64\\\\W=\sqrt{64}$

Width, W = 8 inches.

For length:

$L=3W\\\\L=3\times8$

L = 24 inches

Find more information: https://brainly.com/question/11037225