Answer:
The answer to your question is 50.76 g of H₂O
Explanation:
Data
mass of water = ?
mass of Li₃N = 32.9 g
Process
1.- Write the balanced chemical reaction
Li₃N + 3H₂O ⇒ 3LiOH + NH₃
2.- Calculate the molar mass of Li₃N and H₂O
Li₃N = (3 x 7) + (1 x 14) = 35 g
H₂O = (2 x 1) + (16 x 1) = 18 g
3.- Use proportions to calculate the mass of water
35 g of Li₃N ---------------- (3 x 18) g of water
32.9 g of Li₃N ------------ x
x = (32.9 x 54)/35
x = 1776.6/35
x = 50.76 g of H₂O
