Question:
Calculate the required amount of heat transfer, in kJ/kg.
Answer:
16.44KJ/Kg
Explanation:
Given
P1 = Initial Pressure = 400KPa
T1 = Initial Temperature = 17°C = 17 + 273 = 290
W,out = Workdone by peddle wheel = 75KJ/Kg
Final Volume = V2 = 3V1
R = Gas Constant of air = 0.287
Given that the system is a close system, the change in energy is given by
∆E = E,in - E,out ----- Energy Balance
∆W = W,in - W,out
The boundary work could be defined as follows:
W,b = RT ln(V2/V1)
W,b = 0.287 * 290 * ln(3V1/V1)
W,b = 83.23 * ln(3)
W,b = 91.44 KJ/Kg ----- W,in
∆W = W,in - W,out
∆W = 91.44 - 75
∆W = 16.44KJ/Kg