Question

A floating ice block is pushed through a displacement images = (15 m)images − (12 m)images along a straight embankment by rushing water, which exerts a force images = (210 N)images − (150 N)images on the block. How much work does the force do on the block during the displacement?

Answer 1

Answer:

Explanation:

Displacement, $\overrightarrow{d}=15\widehat{i}-12\widehat{j}$

force, $\overrightarrow{F}=210\widehat{i}-150\widehat{j}$

Work done is defined as the product of force and the displacement in the direction of force.

$W=\overrightarrow{F}.\overrightarrow{d}$

$W=\left ( 210\widehat{i}-150\widehat{j} \right ).\left ( 15\widehat{i}-12\widehat{j} \right )$

W = 3150 + 1800

W = 4950 J