Answer:
The magnet applies a magnetic field 0.7 * 10^-5 T at distance 0.51 m
Explanation:
Solution
The magnetic field is produced due to the orientation of the electrons in their orbits in the material of the magnet where the bar magnet is a magnetic dipole where the magnetic field produced due to the magnet is given by
B_a=μ_o*2μ/4*π*r^3 (1)
Where μ is the magnetic dipole, the term μ_o/4*π is constant and equals 1 x 10 ^-7 T.m^2/C.m/s and r is the distance from the magnet to the location where the magnetic field is applied. μ is the magnetic dipole.
As shown by equation (1), the magnetic field is inversely proportional to
r_3 (B ∝ 1/r^3). therefore, for two instants r1 and r2, we could get the next r3 relationship in the form
B_1/B_2=r_2^2/r_1^3
B_2=(r_1^3/r_2^3)B_1 (2)
Where B_1 = 3 x 10^ -5 T, r_1 = 0.17 m and r_2 = 0.51 m. Now we can plug our values for B_1, r_1 and r_2 into equation (2) to get B_2
B_2=(r_1^3/r_2^3)B_1
=0.7 * 10^-5 T
The magnet applies a magnetic field 0.7 * 10^-5 T at distance 0.51 m
