Question

The reaction of UO2+ with hydrogen ion in aqueous solution 2 UO2+ + 4 H+U4+ + UO22+ + 2 H2O is second order in UO2+ and third order overall. Complete the rate law for this reaction in the box below. Use the form k[A]m[B]n... , where '1' is understood for m, n ... (don't enter 1) and concentrations taken to the zero power do not appear. Rate =

Answer 1

Answer:

Rate law of reaction :$R=k[UO_2^{+}]^2[H^+]^1$

Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

Order of the reaction = Sum of stoichiometrix coefficients coming in rate law of reaction.

$2 UO_2^{+} + 4 H^+\rightarrow U^{4+} + UO_2^{2+} + 2 H_2O$

Overall order of the reaction is = 3

Order of the recation with respect to $UO_2^{+}=2$

Rate law of reaction can be written as :

$R=k[UO_2^{+}]^2[H^+]^x$

3 = 2 + x

x = 3 - 2 = 1

Rate law of reaction :$R=k[UO_2^{+}]^2[H^+]^1$