The root-mean-square speed (thermal speed) for a certain gas at 100 degree C is 0.500 km/s. If the temperature of the gas is now increased to 200 degree C, the root-mean-square(thermal) speed will be closest to 563 m/s. 1000 m/s 634m/s 707 m/s 804 m/s

Respuesta :

Answer: 707m/s

Explanation:

The formulae for the thermal speed (Vrms) is given below as

Vrms =√3KT/m

K, T and m are all constants which implies that

Vrms is proportional to the square root of temperature.

That's (Vrms)1/√T1 = (Vrms)2/√T2

(Vrms)1 = 0.5km/s, T1 = 100°c, (Vrms)2 =?, T2 = 200°c

By substituting we have that

0.5/√100 = (Vrms)2/√200

By cross multiplication

0.5×√200 = (Vrms)2×√100

0.5 × √200 = (Vrms)2 × 10

(Vrms)2 = (0.5 × √200)/10

(Vrms)2 = 0.707 km/s.

By converting to m/s, we multiply 0.707 km/s by 1000

(Vrms)2 = 0.707×1000 = 707 m/s

The velocity of the gas at a temperature of 200°C is 563 m/s.

Relationship between root-mean-square speed and temperature

The rms velocity (v) is directly proportional to the square root of temperature(T).

v = k√T

When T = 100°C = 373 K, v = 0.5 km/s, hence:

0.5 = k√373

k = 0.5/√373

For temperature of 200°C, T = 473:

v = (0.5/√373) * √473 = 0.563 km/s = 563 m/s

The velocity of the gas at a temperature of 200°C is 563 m/s.

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