Answer:
The mixture contains 47 lb of Colombian Supreme and 3 lb of Mocha Java.
Step-by-step explanation:
We are given the following in the question:
Let x be the amount of Colombian supreme and y be the amount of Mocha java in the mixture.
Total amount of mixture = 50 lb
Thus, we can write the equation:
[tex]x + y =50[/tex]
Total unit cost of mixture = $5.93/lb
Cost of Colombian Supreme = $4.99/lb
Cost of Mocha Java = $5.99/lb
Thus, we can write the equation:
[tex]\dfrac{4.99x+5.99y}{50}=5.93\\\\4.99x+5.99y=296.5[/tex]
Solving the two equations by elimination method,
[tex]4.99x+5.99y-4.99(x+y)=296.5-4.99(50)\\y=47\\x = 50-y=3[/tex]
Thus, the mixture contains 47 lb of Colombian Supreme and 3 lb of Mocha Java.