Answer:
[tex]p_n = 135(1.05)^n[/tex]
Step-by-step explanation:
In the situation of this problem, we have:
- The initial college's tuition per hour is
[tex]p_0 = 135\$[/tex]
- Then, we know that the price increases by 5% each year. This means that its value increases by
[tex](1+\frac{5}{100})[/tex] each year, which is equivalent to
[tex](1+\frac{5}{100})=1.05[/tex] each year
So, after 1 year, the price will be
[tex]p_1 = 1.05 p_0[/tex]
After 2 year, the price will be
[tex]p_2 = 1.05 p_1 = 1.05(1.05 p_0)=1.05^2 p_0[/tex]
So after n years, the price will be
[tex]p_n = 1.05^n p_0[/tex]
And by substituting the value of p0, we find the final expression:
[tex]p_n = 135(1.05)^n[/tex]
where n is the number of years.