Answer:
The answer to the question is
The probability is 0.9 or 90 %
Step-by-step explanation:
To solve the question, we note that
Number of population sampled = 250
Percentage that access the internet at work = 74 % = P(A)
The number that access the internet at home = 88% while = P(B)
The number that access the internet at home and at work = 72 % hence =P(C)
The probability that a person in this sample selected at random accesses the Internet at home or at work is given by P(A) U P(B) - P(AnB)
Which gives 0.74+0.88-0.72 = 0.9 or 90 %