Question

176 employees of your firm were asked about their job satisfaction. Out of the 176, 157 said they were unsatisfied.
1. What is the estimate of the population proportion?
2. What is the standard error of this estimate?

Answer 1

Answer:

1. $p = 0.8920$

2. $SE_{p} = 0.0234$

Step-by-step explanation:

A proportion p is the number of desired outcomes divided by the number of total outcomes.

The standard error of a proportion is given by:

$SE_{p} = \sqrt{\frac{p(1-p)}{n}}$

In which n is the number of people asked.

1. What is the estimate of the population proportion?

157 unsatisfied

176 employees

$p = \frac{157}{176} = 0.8920$

2. What is the standard error of this estimate?

$SE_{p} = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.8920*0.1080}{176}} = 0.0234$