Answer:
a. 1.6π*10⁵rads/secs
b. 90⁰
c. 39.8ohms
d. 0.04997μF
e. 39.8ohms
Explanation:
a. From the question, the frequency is given as 80KHz. The angular frequency is expressed as
W=2πf
w=2*π*80000
w=1.6π*10⁵rads/secs
b. To determine the phase angle of the current, from general ohms law
I=V/Y
where Y is the capacitive reactance
expressed as
Y=1/wc.
Also in an RC circuit the voltage lags the current
Hence expressing in polar form,
I=0.025wc<(0+90)
I=0.025wc<90⁰
The required phase angle is 90⁰
c. from the equation above the magnitude is
I=0.025wc,
if we substitute the value of the current as 628.3μA and w=1.6π*10⁵rads/secs
we have
C= (628.3μ)/(0.025*1.6π*10⁵)
C=0.04997μF
The reactance is expressed as
Y=1/wc
Y=1/(1.6π*10⁵*0.04997*10⁻⁶)
Y=39.8ohms
d. as calculated above the capacitance of the capacitor is
0.04997μF.
e. since the impedance is express mathematically as
Z=√(Y²)=39.8ohms