(1 point) Find two unit vectors orthogonal to a=⟨4,5,0⟩a=⟨4,5,0⟩ and b=⟨0,1,−3⟩b=⟨0,1,−3⟩ Enter your answer so that the first non-zero coordinate of the first vector is positive. First Vector: ⟨⟨ , , ⟩⟩ Second Vector: ⟨⟨ , , ⟩

Respuesta :

Answer:

 First vector

[tex]V=+ \dfrac{-15i+12j+4k}{\sqrt{385}}[/tex]

Second vector

[tex]V=- \dfrac{-15i+12j+4k}{\sqrt{385}}[/tex]

Step-by-step explanation:

Given that

Vector a ,  a= 4 i + 5 j + 0 k

Vector b , b= 0 i + 1 j  - 3 k

The orthogonal vector V is given as

V = a x b

V is the cross product of the above two vector which is orthogonal to the vectors a and b.

[tex]V=\begin{vmatrix}i & j & k\\ 4 & 5 & 0\\ 0& 1 &-3 \end{vmatrix}\\V=i(-15-0)-j(-12-0)+k(4-0)\\V=-15i+12j+4k[/tex]

The unit vectors

[tex]V=\pm \dfrac{-15i+12j+4k}{\sqrt{15^2+12^2+4^2}}\\\\V=+\dfrac{-15i+12j+4k}{\sqrt{385}}\\V=-\dfrac{-15i+12j+4k}{\sqrt{385}}[/tex]

First vector

[tex]V=+ \dfrac{-15i+12j+4k}{\sqrt{385}}[/tex]

Second vector

[tex]V=- \dfrac{-15i+12j+4k}{\sqrt{385}}[/tex]

As 2 points of the vectors orthogonal to a point of a =⟨4,5,0⟩a=⟨4,5,0⟩ and b=⟨0,1,−3⟩b=⟨0,1,−3⟩. They have a no zero at the zero coordinates of the firs t and the second vector.  

  • Vector a ,  a= 4 i + 5 j + 0 k , Vector b , b= 0 i + 1 j  - 3 k
  • orthogonal vector V is given as the
  • V = a x b , V is the cross the product of the above 2 vector which is orthogonal to the vectors the a and b.

Learn more about the vectors orthogonal.

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