Respuesta :
Answer:
First vector
[tex]V=+ \dfrac{-15i+12j+4k}{\sqrt{385}}[/tex]
Second vector
[tex]V=- \dfrac{-15i+12j+4k}{\sqrt{385}}[/tex]
Step-by-step explanation:
Given that
Vector a , a= 4 i + 5 j + 0 k
Vector b , b= 0 i + 1 j - 3 k
The orthogonal vector V is given as
V = a x b
V is the cross product of the above two vector which is orthogonal to the vectors a and b.
[tex]V=\begin{vmatrix}i & j & k\\ 4 & 5 & 0\\ 0& 1 &-3 \end{vmatrix}\\V=i(-15-0)-j(-12-0)+k(4-0)\\V=-15i+12j+4k[/tex]
The unit vectors
[tex]V=\pm \dfrac{-15i+12j+4k}{\sqrt{15^2+12^2+4^2}}\\\\V=+\dfrac{-15i+12j+4k}{\sqrt{385}}\\V=-\dfrac{-15i+12j+4k}{\sqrt{385}}[/tex]
First vector
[tex]V=+ \dfrac{-15i+12j+4k}{\sqrt{385}}[/tex]
Second vector
[tex]V=- \dfrac{-15i+12j+4k}{\sqrt{385}}[/tex]
As 2 points of the vectors orthogonal to a point of a =⟨4,5,0⟩a=⟨4,5,0⟩ and b=⟨0,1,−3⟩b=⟨0,1,−3⟩. They have a no zero at the zero coordinates of the firs t and the second vector.
- Vector a , a= 4 i + 5 j + 0 k , Vector b , b= 0 i + 1 j - 3 k
- orthogonal vector V is given as the
- V = a x b , V is the cross the product of the above 2 vector which is orthogonal to the vectors the a and b.
Learn more about the vectors orthogonal.
brainly.com/question/15587050.