Question

Question 21
0.1 pts
Given the following equation:
2 Al(s) +3 FeO(s) 3Fe(s)+ Al2O3(s)
How many moles of aluminum are needed to react completely with 1.2 moles of
FeO?
24n
1.2 n
oooo
8n
1.6n

Answer 1

Answer:

$\large \boxed{\text{0.8 mol of Al}}$

Explanation:

We will need a balanced equation with moles, so let's gather all the information in one place.

             2Al + 3FeO ⟶ 3Fe + Al₂O₃

n/mol:               1.2

2 mol of Al react with 3 mol of FeO

$\text{Moles of Al} = \text{1.2 mol Fe}\times \dfrac{\text{1 mol Al }}{\text{3 mol Fe}}= \textbf{0.8 mol Al}\\\\\text{The reaction will need \large \boxed{\textbf{0.8 mol of Al}} }$