Question

A 0.47 kg object is attached to a spring with a spring constant 146 N/m so that the object is allowed to move on a horizontal frictionless surface. The object is released from rest when the spring is compressed 0.1 m. Find the force on the object when it is released.

Answer 1

Answer:

14.6 N

Explanation:

Force: This can be defined as the product of mass and acceleration. The S.I unit of Force is Newton(N).

From Hook's law,

F = ke ..................... Equation 1

Where F = Force on the object, k = spring constant, e = compression.

Given: k = 146 N/m, e = 0.1 m.

Substitute into equation 1

F = 146(0.1)

F = 14.6 N.

Hence the force on the object = 14.6 N