Question

A country has two official languages, English and French. Choose a citizen at random and ask, "What is your mother tongue?" Here is the distribution of responses, combining many separate languages from the broad Asian/Pacific region. Language English French Asian/Pacific Other Probability 0.51 ? 0.08 0.22 (a) What probability should replace "?" in the distribution? (b) What is the probability that a citizen's mother tongue is not English? Explain how you computed your answer. We wish to find P(a citizen's mother tongue is not English). Recall that the complement of an event consists of all the outcomes not in the event. Therefore, the event "a citizen's mother tongue is English" the complement of the event "a citizen's mother tongue is not English". Recall that the rule states the following (where event AC is the complement of event A). P(AC) = 1 + P(A) P(AC) = 1 · P(A) P(AC) = 1 ? P(A) Applying this rule and recalling that we are given P(a citizen's mother tongue is English) = 0.51 gives the result.

Answer 1

Answer: (a) 0.19 (b) 0.49

Step-by-step explanation:

The given probability distribution is,

X English French Asian/Pacific Other

P(X) 0.51 ? 0.08 0.22

a)We not that the some of all probability of a distribution is always 1.

i.e., 0.51+ ? + 0.08 + 0.22 =1.

=> ? =1-(0.51+0.08+0.22) = 0.19

Ans:- 0.19

b)P(Ac)= 1- P(A)

=> P(a citizen's mother tongue is not English) = 1- P(a citizen's mother tongue is English) = 1- 0.51 = 0.49