Answer:
a. Yes
See explanation below.
Step-by-step explanation:
Assuming that if the question is if we can use the normal approximation for the true proportion.
For this case we have n = 40 and p = 0.3 (probability of success)
We need to check some conditions:
1) Random sample : This condition is satisfied since the problem says that she randomly select 40 records
2) [tex] n \hat p = 40*0.3 =12 \geq 10[/tex]
[tex] n(1-\hat p)= 30 *(1-0.3) = 28 \geq 10)[/tex]
3) 10% condition: the random sample is assumed to be less than 10% of the original population size (assumed)
The population proportion have the following distribution
[tex]p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})[/tex]
So then as we can see the normal approximation for this case makes sense since we have all the 3 conditions satisfied so then the answer would be:
a. Yes