Question

What is the solution set of the quadratic inequality 4(x + 2)^2≤0?
{x| x=-2}
{x|x € ℝ}
{x|x= 2}
0

Answer 1

Answer:

{x | x = 2}

Step-by-step explanation:

4(x + 2)² ≤ 0

(x + 2)² ≤ $\frac{0}{4}$

Simplifying this gives;

x² - 4x + 4 ≤ 0

Applying the quadratic formula we get;

x ≤ 2

But the quadratic equation above have only one solution so the answer is ;

{x | x = 2}

Answer 2

The solution set of the quadratic inequality is {x|x= 2}

Computation:

The equation will use the cross-division method along with the quadratic expression of:

$(a+b)^2=a^2-2ab+b^2$

In the given expression:

a is x

b is 2

Solving the quadratic equation:

$4(x + 2)^2 \leq 0\\(x+2)^2\leq \frac{0}{4}\\(x+2)^2=0$

Now, simplifying the expression:

$(x+2)^2\\x^2-4x+4$

Applying the quadratic formula we get;

$x \leq 2$

As, the quadratic equation is having only one solution for the expression, therefore the value of x will be equal to 2 only.

Thus, the correct, solution for the set expression is  {x|x= 2}

To know more about quadratic equations, refer to the link:

https://brainly.com/question/17177510