Answer:
11.072 g
Explanation:
2 C3H6 (g) + 2NH3 (g) + 3O2 (g) = 2C3H3N (g) + 6H2O (g)
molar mass of Acrylonitrile (C3H3N) = 53.06 g/mol
molar mass of C3H6 = 42.08 g/mol =
molar mass of NH3 = 17.031 g/mol
molar mass of O2 = 15.999 g/mol
mole of C3H6 = 15 g / 42.08 g/mol = 0.3565 mol
mole of NH3 = 5 g / 17.031 g/mol = 0.294 mol
mole of O2 = 10 g / (15.999 x 2g/mol) = 0.313
finding the limiting reagent be comparing the mole
2 mole of C3H6 react with 2 mole of NH3 and 3 mole of O2 to yield 2 mole of C3H3N
0.209 mole of C3H6 react with 0.209 mole of NH3 and 0.313 oxygen
mass of Acrylonitrile (C3H3N) = 53.06 g/mol × 0.209 mol = 11.072 g