what are the x-intercepts of the graph of the function f(x) = x2 4x – 12? (–6, 0), (2,0) (–2, –16), (0, –12) (–6, 0), (–2, –16), (2, 0) (0, –12), (–6, 0), (2, 0)
f(x) = x^2 + 4x - 12 x-intercepts are the values of x when y = 0 x^2 + 4x - 12 = 0 (x - 2)(x + 6) = 0 x - 2 = 0 or x + 6 = 0 x = 2 or x = -6 Therefore the x-intercepts are (-6, 0), (2, 0)
