Answer:
Momentum of Block B after collision is 200 kg.m/s
Explanation:
Momentum of block A before collision is [tex]p_{1A} = 450kg.m/s[/tex]
Momentum of block B before collision is [tex]p_{1B} = -150kg.m/s[/tex]
Momentum of block A after collision is [tex]p_{2A} = 100kg.m/s[/tex]
According to conservation of momentum, total momentum before collision is equal to total momentum after collision
[tex]p_{1A}+p_{1B}=p_{2A}+p_{2B}\\450-150=100+p_{2B}\\p_{2B}=300-100\\p_{2B}=200 kg.m/s[/tex]
Momentum of Block B afterwards is 200 kg.m/s