(3) Area of the figure = 17 ft²
(4) Area of the figure = 30.28 m²
Solution:
(3) The given image is splitted into two shapes.
One is small rectangle and the other is large rectangle.
Length of the small rectangle = 5 ft – 3 ft = 2 ft
Width of the small rectangle = 1 ft
Area of the small rectangle = length × width
= 2 ft × 1 ft
Area of the small rectangle = 2 ft²
Length of the large rectangle = 5 ft
Width of the large rectangle = 4 ft – 1 ft = 3 ft
Area of the large rectangle = length × width
= 5 ft × 3 ft
Area of the large rectangle = 15 ft²
Area of the figure = 2 ft² + 15 ft²
Area of the figure = 17 ft²
(4) The given image is splitted into two shapes.
One is rectangle and the other is semi-circle.
Length of the rectangle = 6 m
Width of the rectangle = 4 m
Area of the rectangle = length × width
= 6 m × 4 m
= 24 m²
Area of the rectangle = 24 m²
Diameter of the semi-circle = 4 m
Radius of the semi-circle = 4 m ÷ 2 = 2 m
Area of the semi-circle = [tex]\frac{1}{2} \ \pi r^2[/tex]
[tex]$=\frac{1}{2} \times 3 .14 \times 2^2[/tex]
[tex]=6.28[/tex]
Area of the semi-circle = 6.28 m²
Area of the figure = 24 m² + 6.28 m²
= 30.28 m²
Area of the figure = 30.28 m²
