If a string has a density of 1.2 g/m and a 329 g weight is attached, what is the expected wave velocity of the string?
Give only the numerical answer to one decimal place without units. Answer will be graded to within +/- 0.5 of the correct answer so do not round until the final answer.

Respuesta :

Answer:

v=51.9

Explanation:

The velocity on a string is:

[tex] v=\sqrt{\frac{T}{\mu}}[/tex] (1)

with T the tension of the string and μ its linear density. By Newton's first law for a uniform string, the tension is the force applied in one extreme of the string, in this case it is the weight attached to it so T=W=mg. Using that on (1):

[tex] v=\sqrt{\frac{mg}{\mu}}=\sqrt{\frac{(329g)(9.81\frac{m}{s^{2}})}{1.2\frac{g}{m}}}[/tex]

[tex] v=51.9 \frac{m}{s}[/tex]

ACCESS MORE