Answer:
v=51.9
Explanation:
The velocity on a string is:
[tex] v=\sqrt{\frac{T}{\mu}}[/tex] (1)
with T the tension of the string and μ its linear density. By Newton's first law for a uniform string, the tension is the force applied in one extreme of the string, in this case it is the weight attached to it so T=W=mg. Using that on (1):
[tex] v=\sqrt{\frac{mg}{\mu}}=\sqrt{\frac{(329g)(9.81\frac{m}{s^{2}})}{1.2\frac{g}{m}}}[/tex]
[tex] v=51.9 \frac{m}{s}[/tex]