i have no clue what the answer is.
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Area of the word ME = 20 square units
Solution:
Picks' Theorem:
[tex]$Area=I+\frac{B}{2}-1$[/tex]
where I is the interior points and B is the points on the boundary.
Let us first find the area of the letter M:
Number of interior points in M = 0
Number of points in the boundary = 22
Using pick's theorem,
Area of M = [tex]0+\frac{22}{2}-1[/tex]
Area of M = 10 square units
Now, find the area of the letter E:
Number of interior points in E = 0
Number of points in the boundary = 22
Using pick's theorem,
Area of E = [tex]0+\frac{22}{2}-1[/tex]
Area of E = 10 square units
Area of the word ME = Area of M + Area of E
= 10 square units + 10 square units
Area of the word ME = 20 square units