Answer:
[tex]2\pi r(r+rx)[/tex]
Explanation:
Let the area of one circular side be given by the formula : [tex]A_{1} = \pi r^{2}[/tex]
However, the wire is a solid cylinder, then it means that the total area is 2 × [tex]\pi r^{2}[/tex] =[tex]2\pi r^{2}[/tex]
However, there is the surface area to consider. This is the curved area of the wire. This is given as:
[tex]A_{2} = lb[/tex]
The length is x.
The breadth is calculated as follows - the length of the circle = [tex]\pi D = 2\pi r[/tex]
Then the area = lb
=[tex]2\pi rx[/tex]
Therefore, the total area is given as [tex]A_{1} + A_{2}[/tex]
= [tex]2\pi r^{2} + 2\pi rx\\ 2\pi r(r+rx)[/tex]