Question

Nitrous oxide, N 2 O , has a mass ratio of nitrogen to oxygen of 1.00 : 0.57 . Determine the ratio by mass of nitrogen to oxygen in dinitrogen trioxide, N 2 O 3 , and dinitrogen pentoxide, N 2 O 5 . N 2 O 3 has a mass ratio of nitrogen to oxygen of 1.00 : N 2 O 5 has a mass ratio of nitrogen to oxygen of 1.00 :

Answer 1

Answer:

$\large\boxed{N_2O_3\text{ has a mass ratio of nitrogen to oxygen of }1.00:1.71}$

$\large\boxed{N_2O_5\text{ has a mass ratio of nitrogen to oxygen of }1.00:2.85}$

Explanation:

1. $N_2O$

Mass ratio: 1.00 : 0.57 (given)

Represent the atomic mass of N by x and the atomic mass of O by y, then:

           $(2x)/y=1/0.57\\\\x/y=1/(2\times 0.57)=1/1.14$

2. $N_2O_3$

Using x and y for the corresponding atomic masses, the mass ratio of $N_2O_3$ is:

          $mass\text{ }ratio=(2x)/(3y)$

Use x/y = 1/1.14

           $mass\text{ }ratio=2x/(3y)=(2/3)(1/1.14)=2/3.42$

Divide both numerator and denominator by 2:

          $mass\text{ }ratio=1.00/1.71$

$\large\boxed{N_2O_3\text{ has a mass ratio of nitrogen to oxygen of }1.00:1.71}$

3. $N_2O_5$

Using x and y for the corresponding atomic masses, the mass ratio of $N_2O_5$ is:

          $mass\text{ }ratio=(2x)/(5y)$

Use x/y = 1/1.14

           $mass\text{ }ratio=(2x)/(5y)=(2/5)(1/1.14)=2/5.7$

Divide both numerator and denominator by 2:

          $mass\text{ }ratio=1.00/2.85$

$\large\boxed{N_2O_5\text{ has a mass ratio of nitrogen to oxygen of }1.00:2.85}$

Answer 2

The mass ratio of $\rm N_2O_3$ has been 1 : 1.71.  The mass ratio of $\rm N_2O_5$ has been 1 : 2.85.

Mass ratio has been defined as the ratio of mass of each element in a molecule.

Computation for mass ratio

The given mass ratio of $\rm N_2O$ has been 1 : 0.57

$\rm \dfrac{2N}{O}=\dfrac{1}{0.57}\\\\ \dfrac{N}{O}= \dfrac{1}{1.14}$

• The mass ratio of $\rm N_2O_3$ has been given as:

$\rm N_2O_3= \dfrac{2N}{3O}\\\\ \dfrac{2N}{3O}=\dfrac{2\;\times\;1}{3\;\times\;1.14}\\ \\ N_2O_3=\dfrac{1}{1.71}$

The mass ratio of $\rm N_2O_3$ has been 1 : 1.71.

• The mass ratio of $\rm N_2O_5$ has been given as:

$\rm N_2O_5= \dfrac{2N}{5O}\\\\ \dfrac{2N}{5O}=\dfrac{2\;\times\;1}{5\;\times\;1.14}\\ \\ N_2O_5=\dfrac{1}{2.85}$

The mass ratio of $\rm N_2O_5$ has been 1 : 2.85.

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