A teachers age is 6 years greater than 2 times a students age. A principals age is 10 years greater than 3 times the students age. If x represents the students age in years, which expression represents how many years older the principal is than the teacher?

Respuesta :

Answer:

The principal is 5 years older than the teacher.

10+(x3)-6+(x2)

Answer:

The expression which represents the relation between the age of principal and teacher is [tex]P-T=x+4[/tex]

And, principal is [tex]x+4[/tex] year older than teacher. Where, [tex]x[/tex] is the age of student.

Step-by-step explanation:

Given information:

The age of teacher [tex]T=2x+6[/tex]

The age of Principal [tex]P=3x+10[/tex]

Where, [tex]x=[/tex] the age of students.

From the above two equation the relation between the age of teacher and principal can be written as:

[tex]P=3x+10[/tex]

[tex]T=2x+6[/tex]

On subtracting , we get

[tex]P-T=x+4[/tex]

Hence, The expression which represents the relation between the age of principal and teacher is [tex]P-T=x+4[/tex]

And principal is [tex]x+4[/tex] year older than teacher. Where [tex]x[/tex] is the age of student.

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